Series Circuit Sample Problem
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In the above problem R1 has a resistance of 50 ohms and R2 has a resistance of 100 ohms.  Knowing that solve the circuit for all parts assuming that 120 V is the power supply.  Use the Ohm's Law and rules of a series circuit to help!
The Rules of a Series Circuit

 1)  Voltage drops around the circuit are divided in proportion to the ohmic value of each component. 

2)  Resistances add directly. (i.e. R1 + R2)

3)  All current flows through all parts. Therefore the amperage on any part of the circuit is the same as the total amperage.

Resistance/R Voltage/E Amperage/I Power/P
RT = 150 ohms ET = 120 V IT = .8 A PT = 96 W
R1 = 50 ohms ER1 = 40 V IR1 = .8 A PR1 = 32 W
R2 = 100 ohms ER2 = 80 V IR2 = .8 A PR2 = 64 W
Step By Step Guide
1. The first step is to add the resistance of the resistors to get the total resistance.  100ohms + 50ohms = 150 ohms

2. From that answer you can solve for the total current using Ohm's Law. 
120V / 150ohms = .8 A

3. Next you plug everything into the Power formula to solve for the total wattage. 
.8A * 120V = 96 W

4. Go through steps 2 and 3 solving for the individual resistors.